3+3sinx=2cos^2x

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Solution for 3+3sinx=2cos^2x equation:


Simplifying
3 + 3sinx = 2cos2x

Solving
3 + 3insx = 2cos2x

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 3insx = -3 + 2cos2x

Combine like terms: 3 + -3 = 0
0 + 3insx = -3 + 2cos2x
3insx = -3 + 2cos2x

Divide each side by '3nsx'.
i = -1n-1s-1x-1 + 0.6666666667cn-1os

Simplifying
i = -1n-1s-1x-1 + 0.6666666667cn-1os

Reorder the terms:
i = 0.6666666667cn-1os + -1n-1s-1x-1

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